如何从c＃代码向exe发送多个参数 [英] How to send multiple parameters to exe from c# code

问题描述

我试图从C＃代码调用exe。如果我从命令提示符如下运行exe，它工作正常

I am trying to invoke exe from C# code . If I run the exe from command prompt like below , it works fine

C:\abc\abc.exe -e dev -l line1 -q 1

我试图通过传递所有三个参数来调用同一个exe没有参数得到传递给exe如果我在Trace中看到它。有人可以告诉我如何通过它。

I am trying to invoke the same exe by passing all three parameters but none of the parameter get pass to exe if I see it in Trace. Can someone tell me how to pass it .

以下是代码

string[] cParams = new string[] { "dev", "Line1", "1" };

ProcessStartInfo startInfo = new ProcessStartInfo(string.Concat(exePath, "abc.exe"));
startInfo.Arguments = "\"" + cParams[0] + " " + cParams[1] + " " + cParams[2] + "\"";
startInfo.RedirectStandardOutput = true;    
startInfo.UseShellExecute = false;
System.Diagnostics.Process.Start(startInfo);

推荐答案

通过将它包含在引号中，一个参数。您还要退出开关（ -e ， -l <​​/ code>， -q ）。我相信你想要的：

By enclosing it in quotes you are in effect passing only one parameter. You are also leaving out the switches (-e, -l, -q). I believe you want:

ProcessStartInfo startInfo = new ProcessStartInfo(string.Concat(exePath, "abc.exe"));
startInfo.Arguments = "-e dev -l line1 -q 1";

或者如果你的参数来自数组：

Or if your "arguments" come from the array:

startInfo.Arguments = string.Format("-e {0} -l {1} -q {2}", cParams);

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