为什么我不能做一个引用的向量？ [英] Why can't I make a vector of references?

问题描述

当我这样做：

std::vector<int> hello;

一切都很棒。但是，当我使它成为引用的向量时：

Everything works great. However, when I make it a vector of references instead:

std::vector<int &> hello;

我得到了可怕的错误，如error C2528：'pointer'：指向引用的指针是非法的。

I get horrible errors like "error C2528: 'pointer' : pointer to reference is illegal".

我想把一堆structs的引用放到一个向量中，这样我就不用再去处理指针了。为什么矢量引起这样的发脾气？

I want to put a bunch of references to structs into a vector, so that I don't have to meddle with pointers. Why is vector throwing a tantrum about this? Is my only option to use a vector of pointers instead?

推荐答案

向量的容器的组件类型必须 可分配 。引用是不可分配的（你只能在声明它们时将它们初始化一次，并且不能让它们稍后引用其他引用）。其他不可分配类型也不允许作为容器的组件，例如向量< const int> 不允许。

The component type of containers like vectors must be Assignable. References are not assignable (you can only initialize them once when they are declared, and you cannot make them reference something else later). Other non-assignable types are also not allowed as components of containers, e.g. vector<const int> is not allowed.

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