编译时断言？ [英] Compile-time assertion?

问题描述

有没有办法，我可以断言两个常量表达式在编译时是相等的？

Is there a way I can assert that two constant expressions are equal at compile time?

例如。我希望这会导致编译时错误

e.g. I want this to cause a compile-time error

enum { foo=263, bar=264 };
SOME_EXPRESSION(foo,bar)

但我希望这不会导致错误

but I want this to not cause an error

enum { foo=263, bar=263 };
SOME_EXPRESSION(foo,bar)

---

编辑：上面被简化了。我的情况更像是

---

edit: the above was simplified. My situation is more like

some_other_file_I_dont_control.h：

some_other_file_I_dont_control.h:

class X
{
public:
   enum { foo=263 };
}

my_file.h：

my_file.h:

enum { bar=something+somethingelse }; // bar should equal X::foo
SOME_EXPRESSION(X::foo, bar)

推荐答案

请参阅 static_assert （仅限C ++ 0x）;如果是旧版本，请参阅 Boost的 StaticAssert 。

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