清理STL列表/指针向量 [英] Cleaning up an STL list/vector of pointers

问题描述

C ++的最短块是什么，你可以想出来安全地清理一个向量或指针列表？ （假设你必须在指针上调用delete）。

What is the shortest chunk of C++ you can come up with to safely clean up a vector or list of pointers? (assuming you have to call delete on the pointers?)

list<Foo*> foo_list;

我宁愿不使用Boost或用智能指针包装我的指针。

I'd rather not use Boost or wrap my pointers with smart pointers.

推荐答案

因为我们在这里扔了ga子...C ++的最短块

Since we are throwing down the gauntlet here... "Shortest chunk of C++"

static bool deleteAll( Foo * theElement ) { delete theElement; return true; }

foo_list . remove_if ( deleteAll );

我想我们可以信任那些提出STL的人有高效的算法。为什么要重新发明轮子？

I think we can trust the folks who came up with STL to have efficient algorithms. Why reinvent the wheel?

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