使用std :: bind与成员函数,使用对象指针或不是这个参数? [英] Using std::bind with member function, use object pointer or not for this argument?

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问题描述

当使用 std :: bind 绑定成员函数时,第一个参数是对象 this 指针。



请参阅以下程序:

  #include< iostream> 
#include< functional>

struct foo
{
void bar(int v){std :: cout< foo :: bar - < v<< '\\\
'; }
};

int main()
{
foo my_foo;

auto f1 = std :: bind(& foo :: bar,my_foo,1);
auto f2 = std :: bind(& foo :: bar,& my_foo,2);

f1();
f2();
}

两个clang和GCC编译这个没有投诉, :

 
foo :: bar - 1
foo :: bar - 2

我一直在试图围绕规范(第20.8.9节),但它是一个非常不清楚的地方。



应该只有一个是正确的,还是正确的?

解决方案

20.8.9.1.2转到20.8.2来描述您对 bind 的调用的要求和效果。 20.8.2是:


20.8.2要求[func.require]



1 定义 INVOKE (f,t1,t2,...,tN)如下:



- (t1。* f)(t2,...,tN) / code>是指向类 T t1 的成员函数的指针是类型 T 或对类型 T 的对象的引用,或对从 T ;



- ((* t1)。* f)当 f 是指向类 T 的成员函数的指针时, code> t1 不是上一个项目中描述的类型之一;



- t1。当 N == 1 f 是指向类的成员数据的指针时, T t1 是类型 T 引用 T 类型的对象或对从 T ;

派生类型的对象的引用当 N == 1 时,

- (* t1)。* f f 是指向类 T t1 不是上一个项目中描述的类型之一;



- f(t1,t2,...,tN) / code>在所有其他情况下。


前两个选项允许引用和指针。

这里需要注意的重要的事情是,不是限制你使用简单的指针。你可以使用一个 std :: shared_ptr 或其他一些智能指针来保持你的实例活着,而绑定它仍然可以使用 std :: bind 作为 t1 被取消引用,无论是什么(给定,当然,这是可能的)。


When using std::bind to bind a member function, the first argument is the objects this pointer. However it works passing the object both as a pointer and not.

See for example the following program:

#include <iostream>
#include <functional>

struct foo
{
    void bar(int v) { std::cout << "foo::bar - " << v << '\n'; }
};

int main()
{
    foo my_foo;

    auto f1 = std::bind(&foo::bar, my_foo, 1);
    auto f2 = std::bind(&foo::bar, &my_foo, 2);

    f1();
    f2();
}

Both clang and GCC compiles this without complaints, and the result works for both binds:

foo::bar - 1
foo::bar - 2

I have been trying to wrap my head around the specification (section 20.8.9) but it's one of the places where it's far from clear to me.

Should only one be correct, or are both correct?

解决方案

Both are correct. 20.8.9.1.2 forwards to 20.8.2 to describe the requirements and the effect of your call to bind. 20.8.2 is:

20.8.2 Requirements [func.require]

1 Define INVOKE(f, t1, t2, ..., tN) as follows:

(t1.*f)(t2, ..., tN) when f is a pointer to a member function of a class T and t1 is an object of type T or a reference to an object of type T or a reference to an object of a type derived from T;

((*t1).*f)(t2, ..., tN) when f is a pointer to a member function of a class T and t1 is not one of the types described in the previous item;

t1.*f when N == 1 and f is a pointer to member data of a class T and t1 is an object of type T or a reference to an object of type T or a reference to an object of a type derived from T;

(*t1).*f when N == 1 and f is a pointer to member data of a class T and t1 is not one of the types described in the previous item;

f(t1, t2, ..., tN) in all other cases.

The first two options allow both a reference and a pointer.

The important thing to notice here is that the wording does not limit you to plain pointers. You could use a std::shared_ptr or some other smart pointer to keep your instance alive while bound and it would still work with std::bind as t1 is dereferenced, no matter what it is (given, of course, that it's possible).

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