我想把std :: string转换成一个const wchar_t * [英] I want to convert std::string into a const wchar_t *
问题描述
有没有方法?
我的电脑是AMD64,
Is there any method? My computer is AMD64,
::std::string str;
BOOL loadU(const wchar_t* lpszPathName, int flag = 0);
:
loadU(&str);
VS2005编译器说:
错误7错误C2664 ::不能将参数1从' std :: string * __ w64'to'const wchar_t *'
the VS2005 compiler says: Error 7 error C2664:: cannot convert parameter 1 from 'std::string *__w64 ' to 'const wchar_t *'
我该如何做?
推荐答案
如果你有一个std :: wstring对象,你可以调用 c_str()
得到一个 wchar_t *
:
If you have a std::wstring object, you can call c_str()
on it to get a wchar_t*
:
std::wstring name( L"Steve Nash" );
const wchar_t* szName = name.c_str();
因为你使用一个窄字符串,你首先需要加宽它。这里有各种选择;一个是使用Windows的内置 MultiByteToWideChar
例程。这将给你一个 LPWSTR
,这相当于 wchar_t *
。
Since you are operating on a narrow string, however, you would first need to widen it. There are various options here; one is to use Windows' built-in MultiByteToWideChar
routine. That will give you an LPWSTR
, which is equivalent to wchar_t*
.
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