为什么在方法参数列表中添加void [英] Why add void to method parameter list

问题描述

我看到了以下签名的方法：

I've seen methods with the following signature:

void foo (void);

他们没有参数，但我想知道这样做是否有用。

They take no argument, however I'm wondering whether doing this is useful or not. Is there a reason why you would want to do it?

推荐答案

C ++ 03的标准说明（强调我的） / p>

The C++03 standard says (emphasis mine):

8.3.5.2

8.3.5.2

参数声明子句be
指定，以及它们的处理，当调用该函数时。 [注：
参数声明子句用于转换在函数调用上指定的参数
;见5.2.2。 ] 如果
parameter-declaration-clause为空，则该函数不接受
参数

The parameter-declaration-clause determines the arguments that can be specified, and their processing, when the function is called. [Note: the parameter-declaration-clause is used to convert the arguments specified on the function call; see 5.2.2. ] If the parameter-declaration-clause is empty, the function takes no arguments.

这意味着如果你正在与编译器交谈只是一个品味问题。

This means that if you are talking to the compiler it's just a matter of taste.

如果你正在编写代码，将被其他人阅读， C ++的做事方式是

If you are writing code that will be read by others, then the C++ way of doing things is

void foo();

另一种形式仅在与C兼容的情况下仍然有效， em>两个签名之间的差异。

The other form remains valid only for reasons of compatibility with C, where there was a difference among the two signatures.

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