什么是scan analougus的scanf格式化输入？ [英] What is the cin analougus of scanf formatted input?

问题描述

对于scanf，通常有一种直接的格式化输入方式：

With scanf there's, usually, a direct way to take formatted input:

1）使用大于0且小于1的实数进行排序。 'x'，例如： 0.32432523x

1) line with a real number higher than 0, and less than 1. Ending on 'x', e.g: 0.32432523x

scanf("0.%[0-9]x", &number);

2）行表示格式为的加法：30 + 28 = / em>

2) line represents an addition in the format :30+28=fifty-eight

scanf(":%d+%d=%99s", &number1, &number2, &total);

cin解决方案是什么，只使用标准库？

What is the cin solution, using only the standard library?

推荐答案

使用>>运算符从cin读取。

Use the >> operator to read from cin.

  int number1, number2;
  std::string text;
  char plus, equals;
  std::cin >> number1 >> plus >> number2 >> equals >> text;
  if (!std::cin.fail() && plus == '+' && equals == '=' && !text.empty())
    std::cout << "matched";

它不如scanf那么好，因为你必须验证scanf字符串中的任何文字自己。使用stream实现比scanf更多的代码行。

It's not as good as scanf because you'd have to verify any literals that were in the scanf string yourself. Doing it with streams will almost certainly be a lot more lines of code than scanf.

我会使用scanf。

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