如何调用基类构造函数？ [英] How do I call the base class constructor?

问题描述

latley我花了很多的Java编程。在这里你调用继承自 super（）; （你可能都知道）的类

在C ++中有一个类，它有一个默认的构造函数，它接受一些参数。示例：

  class BaseClass {
 public：
 BaseClass（char * name）; .... 
  

如果我继承该类，它会给我警告，没有适当的默认构造函数。所以在C ++中有一些类似于 super（）的东西，还是我需要定义一个函数来初始化所有的变量？

 <$ c $ 
 c> class Foo：public BaseClass {
 public：
 Foo（）：BaseClass（asdf）{} 
}; 
  

接受参数的基类构造函数必须在初始化成员之前调用。

latley I spent much programming in Java. There you call the class you Inherited from with super(); (you all probably know that)

Now I have a class in C++ which has a default constructor which takes some arguments. Example:

class BaseClass {
public:
    BaseClass(char *name); .... 

If I inherit the class it gives me the warning, that there is no appropriate default constructor available. So is there something like super() in C++, or do I have to define a function where I initialize all variables?

解决方案

You do this in the initializer-list of the constructor of the subclass.

class Foo : public BaseClass {
public:
    Foo() : BaseClass("asdf") {}
};

Base-class constructors that take arguments have to be called there before any members are initialized.

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