为什么将“float **”转换为“const float **”时出现错误？ [英] Why am I getting an error converting a ‘float**’ to ‘const float**’?

问题描述

我有一个函数接收 float ** 作为参数，我试图改变它采取 const float ** 。

I have a function that receives float** as an argument, and I tried to change it to take const float**.

编译器（ g ++ ）不喜欢它并发出：

The compiler (g++) didn't like it and issued :

从float **到const float **的无效转换

这对我没有意义，我知道（和验证），我可以传递 char * 到一个函数 const char * ，为什么不用 const float ** ？

this makes no sense to me, I know (and verified) that I can pass char* to a function that takes const char*, so why not with const float**?

推荐答案

请参阅为什么我在转换Foo **时遇到错误const Foo **？

See Why am I getting an error converting a Foo** → const Foo**?

因为转换 Foo ** → const Foo ** 将无效和危险...转换从 Foo ** → const Foo ** 是危险的，它会让你静默和不小心修改一个const Foo对象没有转换

Because converting Foo** → const Foo** would be invalid and dangerous ... The reason the conversion from Foo** → const Foo** is dangerous is that it would let you silently and accidentally modify a const Foo object without a cast

引用继续给出一个隐式转换如何允许我修改 const 对象没有转换的例子。

The reference goes on to give an example of how such an implicit conversion could allow me one to modify a const object without a cast.

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