类型“char *”的参数与类型“LPWSTR”的参数不兼容。 [英] Argument of type "char *" is incompatible with parameter of type "LPWSTR"

问题描述

这可能已经问过，但我似乎找不到解决方案：

This has probably been asked before but I can't seem to find the solution:

std::string GetPath()
{
    char buffer[MAX_PATH];
    ::GetSystemDirectory(buffer,MAX_PATH);
    strcat(buffer,"\\version.dll");

    return std::string(buffer);
}

这会返回一个错误，说明：

This returns an error stating:

argument of type "char *" is incompatible with parameter of type "LPWSTR"

所以是啊。任何人都得到了答案？

So yeah. Anyone got an answer?

推荐答案

您需要使用ansi版本：

You need to use the ansi version:

std::string GetPath()
{
     char buffer[MAX_PATH] = {};
     ::GetSystemDirectoryA(buffer,_countof(buffer)); // notice the A
     strcat(buffer,"\\version.dll");

     return std::string(buffer);
 }

或使用unicode：

Or use unicode:

std::wstring GetPath()
{
     wchar_t buffer[MAX_PATH] = {};
     ::GetSystemDirectoryW(buffer,_countof(buffer)); // notice the W, or drop the W to get it "by default"
     wcscat(buffer,L"\\version.dll");

     return std::wstring(buffer);
 }

不是明确调用A / W版本，并将整个项目配置为使用ansi / unicode。所有这些都是更改一些#defines替换foo与fooA / W。

Rather than call the A/W versions explicitly you can drop the A/W and configure the whole project to use ansi/unicode instead. All this will do is change some #defines to replace foo with fooA/W.

请注意，你应该使用_countof（）避免不正确的大小，取决于缓冲区类型。

Notice that you should use _countof() to avoid incorrect sizes depending on the buffers type too.

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