如何使用C ++ 11 std :: stoi与gcc？ [英] How to use C++11 std::stoi with gcc?

问题描述

可能重复：

$ b $

b

我正在使用Qt Creator 2.5.0 和gcc 4.7（Debian 4.7.2 -4）。我添加了QMAKE_CXXFLAGS + = -std = c ++ 11到.pro文件。一切似乎都OK，我使用C ++ 11 std :: for_each等。但是当我包含string头并想使用stoi，我得到以下错误：

  performer.cpp：错误：'std :: string'没有名为'stoi'的成员
  

MinGW 和一个更多，以 Eclipse CDT ，他们有他们的答案。但是我使用Linux，为什么它不在这里工作？

解决方案

  #include< iostream> 
 #include< string> 
 
 int main（）
 {
 std :: string test =45; 
 int myint = stoi（test）; 
 std :: cout<< myint<< '\\\
'; 
} 
  

或

  #include< iostream> 
 #include< string> 
 
使用命名空间std 
 
 int main（）
 {
 string test =45; 
 int myint = stoi（test）; 
 cout<< myint<< '\\\
'; 
} 
  

查看 http://en.cppreference.com/w/cpp/string/basic_string/stol

Possible Duplicate:
How to convert a number to string and vice versa in C++

I am using Qt Creator 2.5.0 and gcc 4.7 (Debian 4.7.2-4). I added "QMAKE_CXXFLAGS += -std=c++11" to .pro file. Everything seems to be OK, I used C++11 std::for_each and so on. But when I included "string" header and wanted to use stoi, i got the following error:

performer.cpp:336: error: 'std::string' has no member named 'stoi'

I found some questions related to MinGW and one more, to Eclipse CDT and they had their answers. But I use Linux, why it is NOT working here?

解决方案

#include <iostream>
#include <string>

int main()
{
    std::string test = "45";
    int myint = stoi(test);
    std::cout << myint << '\n';
}

or

#include <iostream>
#include <string>

using namespace std    

int main()
{
    string test = "45";
    int myint = stoi(test);
    cout << myint << '\n';
}

look at http://en.cppreference.com/w/cpp/string/basic_string/stol

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