无符号整数与for循环的反向迭代 [英] Unsigned int reverse iteration with for loops

问题描述

我想要一个for循环中的迭代器变量作为 unsigned int 反向迭代为0，我不能想到一个类似的比较 i。 -1 ，如果它是一个 signed int 。

  for（unsigned int i = 10; i <= 10 ;-i）{...} 
  

但这似乎很不清楚，因为它依赖于无符号整数的数字溢出高于10。 / p>

也许我只是没有一个清晰的头，但什么是更好的方法来做这个...

免责声明：这只是一个简单的用例，10的上限是微不足道的，它可以是任何东西， i code> unsigned int 。

解决方案

您可以使用

  for（unsigned int j = n; j--> 0;）{} 
  

从 n-1 向下到 0 。

I want the iterator variable in a for loop to reverse iterate to 0 as an unsigned int, and I cannot think of a similar comparison to i > -1, as you would do if it was a signed int.

for (unsigned int i = 10; i <= 10; --i) { ... }

But this seems very unclear, as it is relying on the numerical overflow of the unsigned integer to be above 10.

Maybe I just don't have a clear head, but whats a better way to do this...

Disclaimer: this is just a simple use case, the upper limit of 10 is trivial, it could be anything, and i must be an unsigned int.

解决方案

You can use

for (unsigned int j = n; j-- > 0; ) {}

It iterates from n-1 down to 0.

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