猜数字 - 无限循环时坏读 [英] Guess the number - Infinite loop when bad read
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问题描述
所以我使这个猜数字游戏在c + +,看起来像这样:
So I am making this Guess the number game in c++ that looks like this:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
srand(time(0));
int secretNumber = rand() % 100 + 1; //Generate "Random number"
int nbrOfGuesses = 0;
int userInput;
cout<<"\t************************************"<<endl;
cout<<"\t* *"<<endl;
cout<<"\t* Guess the number! *"<<endl;
cout<<"\t* *"<<endl;
cout<<"\t************************************"<<endl;
cout<<endl;
cout << "Try to find the secret int number: " << endl;
//While input is good
while(cin.good())
{
//Do this
do {
cin>>userInput;
nbrOfGuesses++;
if (userInput>secretNumber)
cout << "Smaller!\n";
else if(userInput<secretNumber)
cout << "Bigger!\n"; // <-- Infinite loop here when you enter something other than an integer
else //Also using this as a backup of (cin.good())
cout << "Something went wrong with the read";
break;
} while(userInput!=secretNumber);
cout << "\nCongratulations! You got it in " << nbrOfGuesses << " guesses\n";
}
system("pause");
return 0;
}
*对不起,如果代码是非常优雅的
*Sorry if the code is note very elegant
正如你所看到的,代码工作得很好,直到你输入一个随机的符号'&'或'j'或任何不是一个整数的其他...然后它循环在cout& <Bigger!;
As you can see, the code works great until you enter a random caracter like '&' or 'j' or anything else that isn't an integer...Then it loops at cout<<"Bigger!";
所以我的问题是:是什么原因造成这种情况?
So my question is: What is causing this?
推荐答案
Check this post, it is about the same problem. To summarize:
cin>>userInput;
if (cin.fail()) {
cout<<"Invalid Entry, please try again."<<endl;
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
感谢ildjarn指向缺少的忽略语句,在帖子中清楚提到我链接到!!
Thanks ildjarn for pointing the missing ignore statement, I missed that part even though its clearly mentioned in the post I linked to!!
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