c ++:使用SQLite创建数据库插入&更新 [英] c++ : Create database using SQLite for Insert & update
问题描述
我试图使用sqlite3 lib创建一个数据库在c + +。我得到错误 sqlite3_prepare_v2'
没有在此范围中声明,如logcat所示。
日志文件
.. \src\Test.cpp:在函数'int main(int,const char **)'中:
..\src\Test.cpp:21:85:错误:'sqlite3_prepare_v2'未在此范围中声明
。 .\src\Test.cpp:30:13:错误:变量'sqlite3在'有初始化器但不完整的类型
..\src\Test.cpp:30:30:错误:无效使用不完整类型'sqlite3 {aka struct sqlite3}'
.. \src\ / sqlite3.h:73:16:错误:正向声明'sqlite3 {aka struct sqlite3}'
$ #include< iostream>
using namespace std;
#includesqlite3.h
int main(int argc,const char * argv []){
sqlite3 * db;
sqlite3_open(test.db,& db);
string createQuery =CREATE TABLE IF NOT EXISTS items(busid INTEGER PRIMARY KEY,ipaddr TEXT,time TEXT NOT NULL DEFAULT(NOW()));;
sqlite3_stmt * createStmt;
cout<< 创建表语句< endl;
sqlite3_prepare_v2(db,createQuery.c_str(),createQuery.size(),& createStmt,NULL);
cout<< 步进表语句< endl;
if(sqlite3_step(createStmt)!= SQLITE_DONE)cout<< 没有创建表! << endl;
string insertQuery =INSERT INTO items(time,ipaddr)VALUES('test','192.168.1.1');; // WORKS!
sqlite3_stmt * insertStmt;
cout<< 创建插入语句< endl;
sqlite3_prepare(db,insertQuery.c_str(),insertQuery.size(),& insertStmt,NULL);
cout<< Stepping Insert Statement< endl;
if(sqlite3_step(insertStmt)!= SQLITE_DONE)cout<< 没有插入项目! << endl;
cout<< 成功! << endl;
return 0;
}
请帮助我。感谢.....
解决方案
#include< sqlite3.h>
应包含sqlite3_prepare_v2和struct sqlite3。确保你包含正确的sqlite3.h文件。
在sqlite3_prepare_v2中,第三个参数可以是(你应该是这样)-1,所以sql是
使用sqlite 3.7.11工作裸机示例:
#include< sqlite3.h>
int test()
{
sqlite3 * pDb = NULL;
sqlite3_stmt * query = NULL;
int ret = 0;
do //避免嵌套if的
{
//初始化引擎
if(SQLITE_OK!=(ret = sqlite3_initialize()))
{
printf (无法初始化库:%d \\\
,ret);
break;
}
//打开到DB的连接
if(SQLITE_OK!=(ret = sqlite3_open_v2(test.db,& pDb,SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE,NULL)))
{
printf(无法打开conn:%d \\\
,ret);
break;
}
//准备语句
if(SQLITE_OK!=(ret = sqlite3_prepare_v2(pDb,SELECT 2012,-1,& query,NULL)))
{
printf(无法准备插入:%d,%s\\\
,ret,sqlite3_errmsg(pDb));
break;
}
//到第一行数据
if(SQLITE_ROW!=(ret = sqlite3_step(query)))//参见文档,这可以返回更多的值as success
{
printf(步骤失败:%d,%s\\\
,ret,sqlite3_errmsg(pDb));
break;
}
// ...并打印列0的值(expect 2012 here)
printf(sqlite:%s,sqlite3_column_text(query,0)
} while(假);
// cleanup
if(NULL!= query)sqlite3_finalize(query);
if(NULL!= pDb)sqlite3_close(pDb);
sqlite3_shutdown();
return ret;
}
希望这有助于
I am trying to create a database in c++ using sqlite3 lib.. I am getting error sqlite3_prepare_v2'
was not declared in this scope as shown in logcat.
log file
..\src\Test.cpp: In function 'int main(int, const char**)':
..\src\Test.cpp:21:85: error: 'sqlite3_prepare_v2' was not declared in this scope
..\src\Test.cpp:30:13: error: variable 'sqlite3 in' has initializer but incomplete type
..\src\Test.cpp:30:30: error: invalid use of incomplete type 'sqlite3 {aka struct sqlite3}'
..\src\/sqlite3.h:73:16: error: forward declaration of 'sqlite3 {aka struct sqlite3}'
Here is my code
#include <iostream>
using namespace std;
#include "sqlite3.h"
int main (int argc, const char * argv[]) {
sqlite3 *db;
sqlite3_open("test.db", & db);
string createQuery = "CREATE TABLE IF NOT EXISTS items (busid INTEGER PRIMARY KEY, ipaddr TEXT, time TEXT NOT NULL DEFAULT (NOW()));";
sqlite3_stmt *createStmt;
cout << "Creating Table Statement" << endl;
sqlite3_prepare_v2(db, createQuery.c_str(), createQuery.size(), &createStmt, NULL);
cout << "Stepping Table Statement" << endl;
if (sqlite3_step(createStmt) != SQLITE_DONE) cout << "Didn't Create Table!" << endl;
string insertQuery = "INSERT INTO items (time, ipaddr) VALUES ('test', '192.168.1.1');"; // WORKS!
sqlite3_stmt *insertStmt;
cout << "Creating Insert Statement" << endl;
sqlite3_prepare(db, insertQuery.c_str(), insertQuery.size(), &insertStmt, NULL);
cout << "Stepping Insert Statement" << endl;
if (sqlite3_step(insertStmt) != SQLITE_DONE) cout << "Didn't Insert Item!" << endl;
cout << "Success!" << endl;
return 0;
}
please help me out. thanks.....
解决方案 #include <sqlite3.h>
should contain sqlite3_prepare_v2 and struct sqlite3. Make sure you're including the right sqlite3.h file.
Also in sqlite3_prepare_v2 the 3rd arg can be (and should be in your case) -1 so the sql is read to the first null terminator.
Working bare-metal sample using sqlite 3.7.11:
#include <sqlite3.h>
int test()
{
sqlite3* pDb = NULL;
sqlite3_stmt* query = NULL;
int ret = 0;
do // avoid nested if's
{
// initialize engine
if (SQLITE_OK != (ret = sqlite3_initialize()))
{
printf("Failed to initialize library: %d\n", ret);
break;
}
// open connection to a DB
if (SQLITE_OK != (ret = sqlite3_open_v2("test.db", &pDb, SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE, NULL)))
{
printf("Failed to open conn: %d\n", ret);
break;
}
// prepare the statement
if (SQLITE_OK != (ret = sqlite3_prepare_v2(pDb, "SELECT 2012", -1, &query, NULL)))
{
printf("Failed to prepare insert: %d, %s\n", ret, sqlite3_errmsg(pDb));
break;
}
// step to 1st row of data
if (SQLITE_ROW != (ret = sqlite3_step(query))) // see documentation, this can return more values as success
{
printf("Failed to step: %d, %s\n", ret, sqlite3_errmsg(pDb));
break;
}
// ... and print the value of column 0 (expect 2012 here)
printf("Value from sqlite: %s", sqlite3_column_text(query, 0));
} while (false);
// cleanup
if (NULL != query) sqlite3_finalize(query);
if (NULL != pDb) sqlite3_close(pDb);
sqlite3_shutdown();
return ret;
}
Hope this helps
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