使用“-fno-exceptions”，“new T”会发生什么？ [英] With "-fno-exceptions", what happens with "new T"?

问题描述

我想知道，如果我使用<$ c $编译我的程序，将会 new T 仍然引用 bad_alloc c> -fno-exceptions 选项禁用异常处理？

I was wondering, will new T still throw bad_alloc if I compile my program using the -fno-exceptions option to disable exception handling?

或者编译器（GCC和clang支持该选项） 新T 到新（nothrow）T ？

Or will the compiler (GCC and clang support that option) implicitly transform the use of new T to new (nothrow) T?

推荐答案

我不能给一个明确的答案围绕-fno异常所有的优点，只是在32位linux机器上的观察，gcc 4.5.1 - bad_alloc抛出和没有 -fno-exceptions

I can't give a definitive answer to all the perks around -fno-exceptions, just the observations on a 32 bit linux machine, gcc 4.5.1 - bad_alloc is thrown with and without -fno-exceptions

[21:38:35 1 ~/tmp] $ cat bad_alloc.cpp

int main()
{
    char* c = new char[4000000000U];
}
[21:38:58 1 ~/tmp] $ g++ bad_alloc.cpp
[21:39:06 1 ~/tmp] $ ./a.out
terminate called after throwing an instance of 'std::bad_alloc'
  what():  std::bad_alloc
Aborted
[21:39:07 1 ~/tmp] $ g++ -fno-exceptions bad_alloc.cpp
[21:39:16 1 ~/tmp] $ ./a.out
terminate called after throwing an instance of 'std::bad_alloc'
  what():  std::bad_alloc
Aborted

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