是否可以禁止在编译时从一个类派生？ [英] Is it possible to forbid deriving from a class at compile time?

问题描述

我有一个值类，根据C ++编码标准，第32项中的描述。总之，这意味着它提供了价值语义，没有任何虚拟方法。

I have a value class according to the description in "C++ Coding Standards", Item 32. In short, that means it provides value semantics and does not have any virtual methods.

我不想让一个类从这个类派生。除了别的，一个原因是它有一个公共的非虚拟析构函数。但是一个基类应该有一个析构函数是public和virtual或protected和nonvirtual。

I don't want a class to derive from this class. Beside others, one reason is that it has a public nonvirtual destructor. But a base class should have a destructor that is public and virtual or protected and nonvirtual.

我不知道写一个值类的可能性，不可能从中得出。我想在编译时禁止它。有没有可能有任何已知的成语呢？如果不是，也许在即将到来的C ++ 0x有一些新的可能性？

I don't know a possibility to write the value class, such that it is not possible to derive from it. I want to forbid it at compile time. Is there perhaps any known idiom to do that? If not, perhaps there are some new possibilities in the upcoming C++0x? Or are there good reasons that there is no such possibility?

推荐答案

即使问题没有标记为C ++ 11，对于在这里的人应该提到，C ++ 11支持新的上下文标识符 final 。请参见 Wiki页

Even if the question is not marked for C++11, for people who get here it should be mentioned that C++11 supports new contextual identifier final. See wiki page

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