C ++：在初始化时定义bitset大小？ [英] C++: Define bitset size at initialization?

问题描述

我想在C ++中创建一个bitset。我做了一点研究。我发现的所有例子都在这里：

I want to make a bitset in C++. I did a bit of research. All examples I found where like this:

bitset<6> myBitset;
// do something with it

但我不知道bitset的大小当我在我的类中定义变量：

But I don't know the size of the bitset when I define the variable in my class:

#include <bitset>
class Test
{
public:
     std::bitset *myBitset;
}

这将无法编译...

这样初始化也不起作用：

And initializing like this also doesn't work:

int size = getDependentSizeForBitset();
myBitset = new bitset<size>();

有任何建议吗？

帮助将非常感激。

Any suggestions?
Help would be very appreciated.

推荐答案

Boost有一个

Boost has a dynamic_bitset you can use.

或者，您也可以使用<$ c $ c> vector< bool> ，它（不幸的是）专门用作bitset。这导致了很多的混乱，一般被认为是一个坏主意。但是这是它的工作原理，所以如果这是你需要的，你可以使用它，我想。

Alternatively, you can use a vector<bool>, which (unfortunately) is specialized to act as a bitset. This causes a lot of confusion, and in general is considered a bad idea. But that's how it works, so if that's what you need, you might as well use it, I suppose.

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