调用exit（）时，析构函数是否运行？ [英] Are destructors run when calling exit()?

问题描述

可能重复：

在C ++中，当应用程序调用exit（3）时，栈上的析构函数应该运行到unwind

$ b b

基本上，当 exit 被调用时静态对象被销毁，执行 atexit 处理程序，刷新和关闭，并删除由 tmpfile 创建的文件。本地自动对象不会被销毁。

调用 abort 会让更少发生：无需清理。

干杯& hth。，

Possible Duplicate:
Will exit() or an exception prevent an end-of-scope destructor from being called?

In C++, when the application calls exit(3) are the destructors on the stack supposed to be run to unwind the stack?

解决方案

C++98 §18.3/8 discusses this.

Essentially, when exit is called static objects are destroyed, atexit handlers are executed, open C streams are flushed and closed, and files created by tmpfile are removed. Local automatic objects are not destroyed. I.e., no stack unwinding.

Calling abort lets even less happen: no cleanup whatsoever.

Cheers & hth.,

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