通过引用一个函数传递一个新构造的对象是否合法？ [英] Is it legal to pass a newly constructed object by reference to a function?

问题描述

具体而言，是以下法律C ++？

Specifically, is the following legal C++?

class A{};

void foo(A*);
void bar(const A&);

int main(void)
{
    foo(&A());  // 1
    bar(A());  // 2
}

它似乎工作正常，但这并不意味着它必然是合法的。是吗？

It appears to work correctly, but that doesn't mean it's necessarily legal. Is it?

编辑 - 更改 A& 到 const A& / code>

推荐答案

1：不允许使用临时地址。 Visual C ++允许它作为一个语言扩展（默认语言扩展）。

1: Taking the address of a temporary is not allowed. Visual C++ allows it as a language extension (language extensions are on by default).

2：这是完全合法的。

2: This is perfectly legal.

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