STL对样的三元组类 - 我自己滚吗？ [英] STL-pair-like triplet class - do I roll my own?

问题描述

我想使用一个三元组类，尽可能类似于std :: pair。 STL似乎没有一个。我不想使用太重的东西，像Boost。有没有一些有用的FOSS非限制性许可三元组类，我可以从某地提起？我应该自己滚吗？

I want to use a triplet class, as similar as possible to std::pair. STL doesn't seem to have one. I don't want to use something too heavy, like Boost. Is there some useful FOSS non-restrictive-license triplet class I could lift from somewhere? Should I roll my own? Should I do something else entirely?

编辑：关于 std :: tuple 。 ..

对一个三元组特定类没有什么好处吗？我的意思是，用tuple，我不能做

Is there really no benefit to a triplet-specific class? I mean, with tuple, I can't do

template<typename T1, typename T2, typename T3> std::tuple<T1, T2, T3> triple;

现在可以吗？

推荐答案

看看 std :: tuple - 它是 std的概括:: pair 。所以这里是一个价值初始化的三元组 int s：

Take a look at std::tuple - it's a generalization of std::pair. So here's a value-initialized triple of ints:

std::tuple<int, int, int> triple;

如果需要，您可以有三元组的类型别名：

If you want, you can have a type alias for triples only:

template<typename T1, typename T2, typename T3>
using triple = std::tuple<T1, T2, T3>;

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