c ++ STL中的正则表达式 [英] Regular expressions in c++ STL

问题描述

STL中有没有任何本地库经过测试和工作没有任何额外的编译器选项？
我尝试使用< regex> ，但编译器输出：

Is there any native library in STL which is tested and works without any extra compiler options? I tried to use <regex>, but the compiler outputs this:

从/usr/include/c++/4.3/regex:40，从main.cpp：5：
/usr/include/c++/4.3/c++0x_warning.h:36:2：error：#error这个文件需要编译器和库支持即将到来的ISO C ++标准C ++ 0x。此支持目前是实验性的，必须使用-std = c ++ 0x或-std = gnu ++ 0x编译器选项启用。

In file included from /usr/include/c++/4.3/regex:40, from main.cpp:5: /usr/include/c++/4.3/c++0x_warning.h:36:2: error: #error This file requires compiler and library support for the upcoming ISO C++ standard, C++0x. This support is currently experimental, and must be enabled with the -std=c++0x or -std=gnu++0x compiler options.

推荐答案

G ++ 4.3（以及推测更新的版本）只是为了达到最大的标准符合性而仔细考虑头文件。

G++ 4.3 (and presumably later versions as well) is just being careful about the header files for maximum standards conformance.

++ 98（当前标准已经存在了一段时间），然后在技术报告1中添加了正则表达式支持，并且头文件位于特殊的 tr1 目录，并且内容在特殊的命名空间 std :: tr1 。

If you're programming in C++98 (the current standard that's been around for a while), then regular expression support was added in tech report 1, and the and the header files are in a special tr1 directory, and the contents are in a special namespace std::tr1.

在新的C ++ 0x标准，正则表达式支持已经被合并到标准库中，因此可以在 regex 和命名空间 std 。

In the new C++0x standard, the regular expression support has been merged into the standard library, so it can be found in the header regex and namespace std.

G ++确保您为您指定的 - std = 版本使用正确的版本

G++ makes sure that you use the right version for the --std= version you specified on the command line, even though internally they're both the same implementation.

因此，为了使正则表达式不需要切换到 - std = c + + 0x ，只是

So to make regex work without switching to --std=c++0x, just

#include <tr1/regex>

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