默认构造函数c ++ [英] Default constructor c++

问题描述

我试图理解默认构造函数（由编译器提供，如果你不写一个）与你自己的默认构造函数。这个简单的类：

  class A 
 {
 private：
 int x; 
 public：
 A（）{std :: cout<< 默认构造函数调用A \\\
; } 
 A（int x）
 {
 std :: cout< 参数构造函数调用A \\\
; 
 this-> x = x; 
} 
}; 
 
 int main（int argc，char const * argv []）
 {
 A m; 
 A p（0）; 
 A n（）; 
 
 return 0; 
} 
  

输出为：

为A调用的默认构造函数

为A调用的参数构造函数

一个有另一个构造函数调用，我的问题是哪一个和哪个类型在这种情况下有

解决方案

  A n（）; 
  

声明一个名为 n 的函数没有参数，并返回 A 。

因为它是一个声明，没有代码被调用/执行没有构造函数）。

在声明之后，你可能会写

  A myA = n（）; 
  

这将编译。但它不会链接！因为没有函数 n 的定义。

I am trying to understand how default constructor (provided by the compiler if you do not write one) versus your own default constructor works.

So for example I wrote this simple class:

class A
{
    private:
        int x;
    public:
        A() { std::cout << "Default constructor called for A\n"; }
        A(int x)
        {
            std::cout << "Argument constructor called for A\n";
            this->x = x;
        }
};

int main (int argc, char const *argv[])
{
    A m;
    A p(0);
    A n();

    return 0;
}

The output is :

Default constructor called for A

Argument constructor called for A

So for the last one there is another constructor called and my question is which one and which type does n have in this case?

解决方案

 A n();

declares a function, named n, that takes no arguments and returns an A.

Since it is a declaration, no code is invoked/executed (especially no constructor).

After that declaration, you might write something like

A myA = n();

This would compile. But it would not link! Because there is no definition of the function n.

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