等同于C ++中的Java静态方法 [英] Equivalent of Java static methods in C++

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本文介绍了等同于C ++中的Java静态方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图在一个C ++类中创建一个方法,可以在不创建该类的实例(像Java中的静态方法)的情况下调用,但我一直遇到此错误: error :

I'm trying to create a method in a C++ class that can be called without creating an instance of the class (like a static method in Java), but I keep running into this error: error: expected unqualified-id before ‘.’ token

这里是我想要编译的.cpp文件:

Here's the .cpp file I'm trying to compile:

using namespace std;
#include <iostream>

class Method {
    public:
    void printStuff(void) {
        cout << "hahaha!";
    }
};

int main(void){
    Method.printStuff(); // this doesn't work as expected!
    return 0;
}


推荐答案

>

In C++ it's

Method::printStuff();

,您必须将方法声明为 static

and you have to declare the method as static.

class Method{
    public:
    static void printStuff(void){
        cout << "hahaha!";
    }
};

:: 范围解析操作符。你可以调用如果它在一个类实例,但实例不是必需的(它是静态和所有...)。

:: is called the scope resolution operator. You can call the method with . if it's on a class instance, but the instance is not required (it being static and all...).

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