我怎么能继承QWidget和QThread？ [英] how can i inherit from both QWidget and QThread?

问题描述

我有这样的类

I have a class like this

class GUI : public QWidget, public QThread

当我这样做时，我得到关于连接信号的错误。 错误说对连接的引用不明确。是否有继承这两种方法的方法？

When I do the above i get errors about connect signals. The error says Reference to "connect" is ambiguous. Is there a way to inherit from both?

谢谢

推荐答案

你不能。 QWidget 和 QThread 继承（非虚拟）从 QObject 。因此，您不具有虚拟推导，因此有两个副本 QObject ，这会混淆编译器。 QObject 是这样专门设计的。请参阅：

You can't. Both QWidget and QThread inherit (non-virtually) from QObject. You therefore do not have virtual derivation, thus two copies of QObject, which confuses the compiler. QObject was specifically designed this way. See:

• http://lists.trolltech.com/qt-interest/2006-10/msg00711.html


• http://www.qtforum.org/article/23295/problem-opening-the-qfiledialog.html

• http://lists.trolltech.com/qt-interest/2006-10/msg00711.html
• http://www.qtforum.org/article/23295/problem-opening-the-qfiledialog.html

有一些人据说绕过这个（现在找不到链接，但它在谷歌，我有两个星期有同样的麻烦前面），但它是不安全的。

There are some who allegedly went around this (can't find the link right now, but it's out there on Google, I had the same trouble two weeks ago), but it is unsafe at best.

编辑：最好的方法可能是让另一个对象从QThread继承，并将该对象作为 GUI class。这是大多数人在这件事上的解决方法。

the best way would probably be to have another object inherit from QThread and keep that object as a member in your GUI class. That is the sort of workaround most people do in this matter.

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