模板函数在作为线程调用时不会编译 [英] Template function will not compile when called as a thread

问题描述

我有与模板函数和线程有关的问题：

I have a problem relating to template functions and threads:

template <class TYPE_size>
void Threader(TYPE_size counter)
{
    counter++;
}
int main()
{
    unsigned int counter = 100;
    thread one(Threader,counter);
    one.join();    
    cout << counter;
}

我得到：

错误：没有匹配的函数调用
âstd:: thread :: thread（，unsigned
int&）â

error: no matching function for call to âstd::thread::thread(, unsigned int&)â

如果我删除模板，它编译，如果我将函数调用更改为标准函数调用而不是

If I remove the template it compiles and if I change the function call to a standard function call rather than a thread (still using the template) it compiles.

有人知道为什么会这样吗？

Does anyone know why this is?

使用Centos5 64位。

I'm using Centos5 64 bit.

 error: no matching function for call to âstd::thread::thread(<unresolved overloaded function type>, unsigned int&)â
/usr/lib/gcc/x86_64-redhat-linux6E/4.4.0/../../../../include/c++/4.4.0/thread:124: note: candidates are: std::thread::thread(std::thread&&)
/usr/lib/gcc/x86_64-redhat-linux6E/4.4.0/../../../../include/c++/4.4.0/thread:122: note:                 std::thread::thread(const std::thread&)
/usr/lib/gcc/x86_64-redhat-linux6E/4.4.0/../../../../include/c++/4.4.0/thread:121: note:                 std::thread::thread()

推荐答案

没有名为Threader的函数。当你写 Threader< int> 或某事时，编译器创建一个函数。如果你写 Threader< float> ，那么编译器创建一个新的函数。您可以提供默认模板参数，也可以在调用时提供参数。

There is no function named Threader. When you write Threader<int> or something, then the compiler creates a function. If you then write Threader<float>, then the compiler creates a new function. You can either provide a default template parameter, or give it a parameter when you call it.

template <class TYPE_size=int>

或

thread one(Threader<int>, counter);

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