什么是“抛出”外面一个catch块呢？ [英] what does "throw;" outside a catch block do?

问题描述

我只是偶然发现这个代码：

I just stumbled this code:

void somefunction()
{
   throw;
}

我不知道：这是什么意思？

and I wonder: what does it mean?

我将问题标记为C ++和Visual C ++，因为我不知道答案。答案可能是与标准或一个特殊的Visual C ++扩展或Visual C ++忽略标准相关。

I tagged the question as C++ and Visual C++ because I did not know the answer. The answer could have been related to the standard or to a special Visual C++ extension or to Visual C++ ignoring the standard. That's why I thought both tags are justified.

推荐答案

当然，可能 somefunction / code>只是从一些 catch 块中调用（猜测，这可能是意图）。

Of course, it's possible that somefunction() is only ever called from inside some catch block (at a guess, that's probably the intent anyway).

如果 throw; 在异常不活动时执行，则调用 terminate（） 15.1 / 8）。

If throw; is executed when an exception is not active, it calls terminate() (§15.1/8).

这篇关于什么是“抛出”外面一个catch块呢？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！