如何告诉gcc在没有中断的情况下对switch / case语句发出警告（或失败）？ [英] How can I tell gcc to warn (or fail) on switch/case statements without a break?

问题描述

我有一个复杂的开关语句，我忘了在之一的结尾放置 break case s。这是相当合法的，因此我有一个下落到下一个情况。

I have a complicated switch statement, and I forgot to put a break at the end of one of the cases. This is quite legal, and as a result I had a fall-through to the next case.

如果我忽略放置一个 break 语句，任何方式有gcc警告（或更好，失败）

Is there any way to have gcc warn (or even better, fail) if I neglect to put a break statement?

我意识到有很多有效的用例（我经常在我的代码中使用它们），如这个问题，所以显然这样的警告（或失败）需要一个简单的豁免，这样我可以很容易地说， 我想在这里落下。

I realize that there are many valid use cases (and I use them often in my code), as exemplified in this question, so obviously such a warning (or failure) would need a simple waiver so that I could easily say, "I do want to fall-through here."

有没有办法告诉gcc这样做？

Is there any way to tell gcc to do this?

推荐答案

在 http://gcc.gnu.org上有关于此类功能（-Wswitch-break）的讨论/bugzilla/show_bug.cgi?id=7652 。但它似乎还没有实现

There's a discussion about such a feature (-Wswitch-break) at http://gcc.gnu.org/bugzilla/show_bug.cgi?id=7652. But it doesn't seem to be implemented yet

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