闰年计算 - 家庭作业 [英] Leap Year Calculation - Homework

问题描述

#include <iostream>
using namespace std;

int main() {
    int what_year;

    cout << "Enter calendar year ";
    cin >> what_year;

    if (what_year - (n * 4) = 0 ) {

        cout << "leap year";
    }

    else
    {
        cout << "wont work";
    }

    system("Pause");
    return 0;
}

尝试为课程创建程序，找到闰年..

Trying to make a program for class, to find a leap year.. not sure how to ask C++ if an integer is divisible by a number?

推荐答案

闰年规则是

 if year modulo 400 is 0 then
   is_leap_year
else if year modulo 100 is 0 then
   not_leap_year
else if year modulo 4 is 0 then
   is_leap_year
else
   not_leap_year

http://en.wikipedia.org/wiki/Leap_year#Algorithm

您可以使用取模运算符查看一个数字是否可以被另一个数字均分，

You can use the modulo operator to see if one number is evenly divisible by another, that is if there is no remainder from the division.

2000％400 = 0 //可以被整除除

2000 % 400 = 0 // Evenly divisible by 400

2001％400 = 1 //不能被400整除

2001 % 400 = 1 // Not evenly divisible by 400

有趣的是，没有应用400部分，这导致2000年2月29日不存在这些系统。

Interestingly, several prominent software implementations did not apply the "400" part, which caused February 29, 2000 not to exist for those systems.

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