C / C ++ - 可执行路径 [英] C/C++ - executable path

问题描述

我想获取当前可执行文件的文件路径，但没有可执行文件名称。

I want to get the current executable's file path without the executable name at the end.

我正在使用：

char path[1024];
uint32_t size = sizeof(path);
if (_NSGetExecutablePath(path, &size) == 0)
    printf("executable path is %s\n", path);
else
    printf("buffer too small; need size %u\n", size);

它可以工作，但这会在末尾添加可执行文件名称。

It works, but this adds the executable name at the end.

推荐答案

dirname（path）;
应该返回路径，也就是在Unix系统上，对于windows，你可以做一些strcpy / strcat魔术。

dirname(path); should return path without executable after you acquire path with, that is on Unix systems, for windows you can do some strcpy/strcat magic.

对于dirname，你需要包含 #include& h> ...

For dirname you need to include #include <libgen.h>...

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