如何编写一个以C ++代码为输入的C ++代码生成器？ [英] How to write a C++ code generator that takes C++ code as input?

问题描述

我们有一个CORBA实现，为我们自动生成Java和C ++存根。因为CORBA生成的代码很难使用，我们需要在CORBA代码周围编写wrapper / helpers。所以我们有一个两步代码生成过程（是的，我知道这是坏）：

CORBA IDL - >恼人的CORBA生成的代码 - >有用的包装/帮助函数

使用Java的反射，我可以检查CORBA生成的代码，并使用它来生成额外的代码。但是，因为C ++没有反射，我不知道如何在C ++方面做到这一点。我应该使用C ++解析器吗？ C ++模板？

TLDR：如何使用生成的C ++代码作为输入生成C ++代码？

解决方案

您是否考虑退一步，使用IDL作为自定义代码生成器的源代码？可能你有一些包装代码隐藏的东西，如复制，var，ptr等。我们有一个基于Ruby的CORBA IDL编译器，目前生成Ruby和C ++代码。这可以通过客户生成器扩展，有关RIDL和R2CORBA，请参见 http://www.remedy.nl 。 / p>

另一种选择是检查我们正在处理的IDL到C ++ 11语言映射，更多细节在 http://taox11.remedy.nl 。这种新的语言映射更容易使用，并使用标准类型和STL容器来处理。

We have a CORBA implementation that autogenerates Java and C++ stubs for us. Because the CORBA-generated code is difficult to work with, we need to write wrappers/helpers around the CORBA code. So we have a 2-step code generation process (yes, I know this is bad):

CORBA IDL -> annoying CORBA-generated code -> useful wrappers/helper functions

Using Java's reflection, I can inspect the CORBA-generated code and use that to generate additional code. However, because C++ doesn't have reflection, I am not sure how to do this on the C++ side. Should I use a C++ parser? C++ templates?

TLDR: How to generate C++ code using generated C++ code as input?

解决方案

Have you considered to take a step back and use the IDL as source for a custom code generator? Probably you have some wrapper code that hides things like duplicate, var, ptr, etc. We have a Ruby based CORBA IDL compiler that currently generates Ruby and C++ code. That could be extended with a customer generator, see http://www.remedy.nl for RIDL and R2CORBA.

Another option would be to check out the IDL to C++11 language mapping we are working on, more details on http://taox11.remedy.nl. This new language mapping is much easier to use and uses standard types and STL containers to work with.

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