按任意键在Linux C ++中继续 [英] Press anykey to continue in Linux C++

问题描述

我不知道如果在linux造成任何不同，但我已经在网上发现这：

I am not sure if being in linux makes any different, but i have found online that this:

    cout << "Press Enter to Continue...";
    cin.ignore(numeric_limits<streamsize>::max(),'\n');

应该足够了，＃include< limits>

Should be sufficient, with #include<limits> in the header of course.

但是，它似乎在我的程序中不起作用。

However, it does not seem to work in my program.

它编译，它运行，但它不等待。

It compiles, it runs, but it does not wait.

基本上，我有一个菜单，导致方法调用显示屏幕上的人的列表。

Basically, i have a menu, which lead to a method call to display a list of people on the screen. I wish to pause that list before the system goes back to the menu.

这是我的菜单中的代码：

Here is my code from the menu:

//Manager's Menu
void SelectionPage::showManagerMenu(){
    char option;
    while(true)
    {
        system("clear");                                                //Clears the terminal
        cout<<"             Flat Manager's Menu"<<endl<<endl;           //Display manager's menu
        cout << "Select Manager option" << endl;
        cout << "a) Add a new Flat Member" << endl;
        cout << "b) Delete an existing Flat Member" << endl;
        cout << "c) List Flat Members" << endl;
        cout << "d) Duties" <<endl;
        cout << "e) Resources" <<endl;
        cout << "f) Reset System" <<endl;
        cout << "q) Exit" << endl;
        cout << "make selection: ";
        cin >> option;

        switch(option) {                                                //Takes the user to the corresponding menu or method
            case 'a':   system("clear");
                        memberList.addNewFlatMember(points);
                    break;
            case 'b':   system("clear");
                        memberList.deleteFlatMember();
                    break;
            case 'c':   system("clear");
                        memberList.listFlatMembers();
                    break;
            case 'd':   system("clear");
                        showDutiesMenu();
                    break;
            case 'e':   system("clear");
                        showResourcesMenu();
                    break;
            case 'f':   //reset();
                    break;
            case 'q':   exit(0);
            default:    cout << "Option not recognised: " << option << endl;
                        showManagerMenu();  
        }
    }
}

是c）它导致：

//Show the current flat population
void MemberManagement::listFlatMembers(){
    cout<<"             Member List"<<endl<<endl;

    importFlatMembers();                                                //get flat member info from file

    for( int count = 0; count<flatMemberList.size(); count++){
        cout << count+1<<". "<<flatMemberList[count].getName() << endl;
    }

    cout << "Press any key to Continue...";
    cin.ignore(numeric_limits<streamsize>::max(),'\n');

    return;

}

<请随时让我知道。

if you want to see any other bit of my code, feel free to let me know.

提前感谢。

推荐答案

In * nix，终端通常在向程序发送任何内容之前等待一整行输入。这是为什么你发布的示例代码说：按Enter键继续...; ，然后丢弃所有内容，直到下一个换行符。

In *nix, terminals usually wait for a whole line of input before sending anything to the program. Which is why the example code you posted said "Press Enter to Continue...";, and then discarded everything until the next newline.

为了避免这种情况，你应该把你的终端放在非规范模式，这可以使用POSIX termios（3） 检查是否按下了键。

To avoid that, you should put your terminal in non-canonical mode, which can be done using the POSIX termios(3) functions, as explained in checking if a key was pressed.

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