重载的构造函数的调用是不明确的 [英] Call of overloaded constructor is ambiguous

问题描述

我试图实现一个面向对象的二叉树，但是，我得到一个重载的构造函数的调用的错误消息是不明确的。问题是，我真的有必要的构造函数，但C ++似乎不认识它。

I am trying to implement an object-oriented binary tree, however, I get the error message of a call of an overloaded constructor being ambiguous. The problem is that I really do have the necessary constructor, yet C++ doesn't seem to recognize it.

我的代码： http://pastebin.com/PM9PDYAN

错误讯息：

56  36  In constructor 'Node::Node(const int&, Node*, Node*, const int&)':
56  36  [Error] call of overloaded 'Node(const int&, Node* const)' is ambiguous
17  3   [Note] Node::Node(const int&, Node*)
15  3   [Note] Node::Node(const int&, const int&, Node*) <near match>
15  3   [Note] no known conversion for argument 2 from 'Node* const' to 'const int&'
37  1   [Note] Node::Node(const int&, Node*, Node*, Node*)

推荐答案

重叠：

Node(const int&, Node* = nullptr, Node* = nullptr, Node* = nullptr);

和：

Node(const int&, Node* = nullptr);

这两个都可以匹配只有 int 或只是 int 和节点* 。

Both of these could match a call with just an int or just an int and a Node *.

看起来还有其他重叠的构造函数。

Looks like there are other overlapping constructors as well.

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