Cout的字符串是给错误和困难的时候一些洞察力帮助pls？ [英] Cout of a string is giving an error and a hard time some insight help pls?

问题描述

我无法找到这段代码中的错误，任何人都可以洞察我吗？我运行调试，但错误是不可理解的。

I cant find the error in this piece of code could anyone please insight me? I ran the debugging but the errors are un-understandable..

#include "stdafx.h"
#include <iostream>

using namespace std;

int main() 
{ 
  string name; 
  cout << "Input your name please?" << endl; 
  cin >> name; 

  if
      {
          (name == "Bart Simpson")  
    cout << "You have been very naughty" << endl; 
  }
return 0;
}

推荐答案

问题：

1. 您有一些缺少的 #include ，这可能导致您的初始编译器错误。


2. 您的如果语句有一个简单的语法错误。


3. 使用流提取运算符绝不会生成一个包含空格的字符串。

1. You have some missing #includes, which probably caused your initial compiler errors.
2. You have a simple syntax error with your if statement.
3. Using the stream extraction operator will never yield a string with whitespace inside of it.

以下内容应符合您的期望：

The following should work as you expect:

#include "stdafx.h"
#include <iostream>
#include <ostream>
#include <string>

using namespace std;

int main()
{
    cout << "Input your name please?" << endl;

    string name;
    getline(cin, name);
    if (name == "Bart Simpson")
    {
        cout << "You have been very naughty" << endl;
    }

    return 0;
}

（您需要包含 string std :: string 和 std :: getline 和 ostream std :: endl 。）

(You need to include string for std::string and std::getline, and ostream for std::endl.)

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