字符串输入xor加密程序 [英] String input xor encryption program

问题描述

描述：

我试图写一个乐趣的基本程序，将输入一个字符串/短语，然后xor加密它，最后cout加密短语。我正在mac上工作，所以我将编译xcode和运行它在终端。

Description:
I am trying to write a basic program for fun that will input a string/phrase then xor encrypt it and in the end cout the encrypted phrase. I am working on a mac so I will be compiling with xcode and running it in terminal.

问题：

输入可以进行加密的字符串时出错，请参阅下面的代码：

Problem:
I am having an error with inputting a string that can be xor encrypted, see code below:

代码：

#include <iostream>
#include <string>
using namespace std;

int main ()
{
string mystr;
cout << "What's the phrase to be Encrypted? ";
//getline (cin, mystr);

char string[11]= getline (cin, mystr); //ERROR: Array must be initialized with brace-enclosed initializer
cout << "Phrase to be Encrypted: " << mystr << ".\n";
char key[11]="ABCDEFGHIJ";  //The Encryption Key, for now its generic
for(int x=0; x<10; x++)
{
    string[x]=mystr[11]^key[x];
    cout<<string[x];
}
return 0;
}

帮助：

请识别并说明或提供示例为什么我收到上面的错误代码。

Help:
please identify and explain or provide examples why I am receiving the error code above.

推荐答案

您不是调用 getline 正确。你还试图使用 string 作为一个变量，当它已经被定义为一个类型。我会尝试更像这样：

You're not calling getline correctly. You're also trying to use string as a variable when it's already defined as a type. I'd try something more like this:

getline(cin, mystr);

string result;

for (int i=0; i<10; i++) {
    result.push_back(mystr[i] ^ key[i]);
    cout << result[i];
}

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