C ++中的正态（高斯）分布函数 [英] Normal(Gaussian) Distribution Function in C++

问题描述

我需要知道一种具有50个数字的高斯分布的方法。我知道Boost库生成随机数。在我的情况下，我不需要随机，我需要50数字的正态分布。有什么办法吗？感谢。

I need to know a way to have Gaussian Distribution of 50 numbers. I know of the Boost library which generates random numbers. In my case i don't need random, i need the normal distribution of 50 numbers. Any way to have that? thanks.

推荐答案

从C ++ 11开始，在标准库中有一个正态（高斯）分布：

As of C++11 there is a normal (gaussian) distribution available in the standard library:

http://www.cplusplus.com/ reference / random / normal_distribution /

平均值和标准偏差在创建时作为参数传递。以上链接提供了一个很好的例子：

The mean value and standard deviation are passed as arguments when creating it. The link above provides a good example:

// normal_distribution
#include <iostream>
#include <random>

int main()
{
  const int nrolls=10000;  // number of experiments
  const int nstars=100;    // maximum number of stars to distribute

  std::default_random_engine generator;
  std::normal_distribution<double> distribution(5.0,2.0);

  int p[10]={};

  for (int i=0; i<nrolls; ++i) {
    double number = distribution(generator);
    if ((number>=0.0)&&(number<10.0)) ++p[int(number)];
  }

  std::cout << "normal_distribution (5.0,2.0):" << std::endl;

  for (int i=0; i<10; ++i) {
    std::cout << i << "-" << (i+1) << ": ";
    std::cout << std::string(p[i]*nstars/nrolls,'*') << std::endl;
  }

  return 0;
}

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