返回一个指向c ++中的向量元素的指针 [英] Returning a pointer to a vector element in c++

问题描述

我在全局范围内有一个myObjects的向量。
我有一个方法使用 std :: vector< myObject> :: const_iterator 遍历向量，找到一个特定的元素。
一旦我找到了所需的元素，我想能够返回一个指针（向量存在于全局范围）。

I have a vector of myObjects in global scope. I have a method which uses a std::vector<myObject>::const_iterator to traverse the vector, and doing some comparisons to find a specific element. Once I have found the required element, I want to be able to return a pointer to it (the vector exists in global scope).

如果我返回 & iterator ，我返回迭代器的地址或迭代器指向的地址吗？

If I return &iterator, am I returning the address of the iterator or the address of what the iterator is pointing to?

我需要将 const_iterator 强制转换回myObject，然后返回该地址

Do I need to cast the const_iterator back to a myObject, then return the address of that??

推荐答案

返回迭代器指向的东西的地址：

Return the address of the thing pointed to by the iterator:

&(*iterator)

/ strong>清除一些混乱：

To clear up some confusion:

vector <int> vec;          // a global vector of ints

void f() {
   vec.push_back( 1 );    // add to the global vector
   vector <int>::iterator it = vec.begin();
   * it = 2;              // change what was 1 to 2
   int * p = &(*it);      // get pointer to first element
   * p = 3;               // change what was 2 to 3
}

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