恢复std :: cout的状态后，操作它 [英] Restore the state of std::cout after manipulating it

问题描述

假设我有这样的代码：

void printHex(std::ostream& x){
    x<<std::hex<<123;
}
..
int main(){
    std::cout<<100; // prints 100 base 10
    printHex(std::cout); //prints 123 in hex
    std::cout<<73; //problem! prints 73 in hex..
}

我的问题是，如果有任何方式恢复cout的状态到其从函数返回后的原始状态？ （有点像std :: boolalpha和std :: noboolalpha ..）？

My question is if there is any way to 'restore' the state of cout to its original one after returning from the function? (Somewhat like std::boolalpha and std::noboolalpha..) ?

谢谢，
Iyer

Thanks, Iyer

推荐答案

Googling给了我这个：

Googling gave me this:

  ios::fmtflags f( cout.flags() );

  //Your code here...

  cout.flags( f );

你可能想把它放在函数的头部和末尾。

You'd probably want to put that at the head and end of your function.

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