使用C ++中的istringstream将字符串拆分为整数 [英] Splitting a string into integers using istringstream in C++
问题描述
我试图使用 istringstream
将一个简单的字符串拆分为一系列整数:
#include< string>
#include< iostream>
#include< sstream>
#include< vector>
using namespace std;
int main(){
string s =1 2 3;
istringstream iss(s);
while(iss)
{
int n;
iss>> n;
cout<< *<< n<< endl;
}
}
我得到:
* 1
pre>
* 2
* 3
* 3
为什么最后一个元素总是出现两次?如何解决?
解决方案这是出来两次,因为你的循环是错误的, http://www.parashift.com/c++-faq-lite/input-output.html#faq-15.5\">http://www.parashift.com/c++-faq-lite/input-output.html# while(iss.eof())与
没有区别。
具体来说,在第三次循环迭代中,
iss> n
成功并获得您的3
,并保持流处于良好状态。由于这个好的状态,循环然后运行第四次,并且直到下一个(第四个)iss>> n
后续失败,循环条件被破坏。但在第四次迭代结束之前,您仍然输出n
...第四次。
p>
#include< string>
#include< iostream>
#include< sstream>
#include< vector>
using namespace std;
int main()
{
string s =1 2 3;
istringstream iss(s);
int n;
while(iss>> n){
cout< *<< n<< endl;
}
}
I'm trying to use
istringstream
to split a simple string into a series of integers:#include <string> #include <iostream> #include <sstream> #include <vector> using namespace std; int main(){ string s = "1 2 3"; istringstream iss(s); while (iss) { int n; iss >> n; cout << "* " << n << endl; } }
And i get:
* 1 * 2 * 3 * 3
Why is the last element always coming out twice? How to fix it?
解决方案It's coming out twice because your looping is wrong, as explained (indirectly) at http://www.parashift.com/c++-faq-lite/input-output.html#faq-15.5 (
while (iss)
is not dissimilar fromwhile (iss.eof())
in this scenario).Specifically, on the third loop iteration,
iss >> n
succeeds and gets your3
, and leaves the stream in a good state. The loop then runs a fourth time due to this good state, and it's not until the next (fourth)iss >> n
subsequently fails that the loop condition is broken. But before that fourth iteration ends, you still outputn
... a fourth time.Try:
#include <string> #include <iostream> #include <sstream> #include <vector> using namespace std; int main() { string s = "1 2 3"; istringstream iss(s); int n; while (iss >> n) { cout << "* " << n << endl; } }
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