C ++方法名称作为模板参数 [英] C++ method name as template parameter

问题描述

如何使方法名称（此处 some_method ）为模板参数？

How do I make the method name (here some_method) a template parameter?

template<typename T>
void sv_set_helper(T& d, bpn::array const& v) {
  to_sv(v, d.some_method());
}

推荐答案

a模板标识符参数，因此您不能将名称作为参数传递。然而你可以把一个成员函数指针作为参数：

There is no such thing as a 'template identifier parameter', so you can't pass names as parameters. You could however take a member function pointer as argument:

template<typename T, void (T::*SomeMethod)()>
void sv_set_helper(T& d, bpn::array const& v) {
   to_sv(v, ( d.*SomeMethod )());
}

假设函数有一个 void 返回类型。您将这样调用它：

that's assuming the function has a void return type. And you will call it like this:

sv_set_helper< SomeT, &SomeT::some_method >( someT, v );

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