C ++模板 - LinkedList [英] C++ Templates - LinkedList

问题描述

编辑 - 在下面回答，错过了斜撑。非常感谢所有。

EDIT -- Answered below, missed the angled braces. Thanks all.

我一直在试图写一个基本的单链表，我可以在其他程序中使用。我希望它能够使用内置和用户定义的类型，这意味着它必须是模板。

I have been attempting to write a rudimentary singly linked list, which I can use in other programs. I wish it to be able to work with built-in and user defined types, meaning it must be templated.

由于这个我的节点也必须模板化，因为我不知道它要存储的信息。我写了一个节点类如下 -

Due to this my node must also be templated, as I do not know the information it is going to store. I have written a node class as follows -

template <class T> class Node
{
    T data; //the object information
    Node* next; //pointer to the next node element

public:
    //Methods omitted for brevity
};

我的链表类在一个单独的类中实现，需要在添加新节点时实例化一个节点到列表的结尾。我已实现如下 -

My linked list class is implemented in a seperate class, and needs to instantiate a node when adding new nodes to the end of the list. I have implemented this as follows -

#include <iostream>
#include "Node.h"
using namespace std;

template <class T> class CustomLinkedList
{
    Node<T> *head, *tail;

public:

    CustomLinkedList()
    {
        head = NULL;
        tail = NULL;
    }

    ~CustomLinkedList()
    {

    }

    //Method adds info to the end of the list
    void add(T info)
    {
        if(head == NULL) //if our list is currently empty
        {
            head = new Node<T>; //Create new node of type T
            head->setData(info);
            tail = head;
        }
        else //if not empty add to the end and move the tail
        {
            Node* temp = new Node<T>;
            temp->setData(info);
            temp->setNextNull();
            tail->setNext(temp);
            tail = tail->getNext();
        }
    }

    //print method omitted
};

我设置了一个驱动程序/测试类如下 -

I have set up a driver/test class as follows -

#include "CustomLinkedList.h"
using namespace std;

int main()
{
    CustomLinkedList<int> firstList;

    firstList.add(32);
    firstList.printlist();
    //Pause the program until input is received
    int i;
    cin >> i;

    return 0;
}

编译时遇到错误 - error C2955：'Node '：使用类模板需要模板参数列表 - 它指向我的add方法中的下面一行代码 -

I get an error upon compilation however - error C2955: 'Node' : use of class template requires template argument list - which points me to the following line of code in my add method -

Node* temp = new Node<T>;

我不明白为什么这没有关于类型的信息，因为它被传递到链表在我的驱动程序类中创建。 我应该如何将类型信息传递给Node？

I do not understand why this has no information about the type, since it was passed to linked list when created in my driver class. What should I be doing to pass the type information to Node?

我应该创建一个私有节点结构而不是一个独立的类，在一个文件中的两个类的方法？我不确定这会克服这个问题，但我认为它可能。如果可能，我宁愿有单独的类。

Should I create a private node struct instead of a seperate class, and combine the methods of both classes in one file? I'm not certain this would overcome the problem, but I think it might. I would rather have seperate classes if possible though.

谢谢，安德鲁。

推荐答案

可能想尝试

Node<T>* temp = new Node<T>;

此外，要获得有关如何设计列表的提示，您可以查看std ::列表，虽然有时可能有点令人沮丧。

Also, to get hints on how to design the list, you can of course look at std::list, although it can be a bit daunting at times.

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