如何从clang中排除头文件？ [英] How to exclude headers from AST in clang?

问题描述

我使用clang生成AST。我有以下文件（lambda.cpp）来解析：

I'm generating AST using clang. I've got following file (lambda.cpp) to parse:

#include <iostream>

void my_lambda()
{
    auto lambda = [](auto x, auto y) {return x + y;};
    std::cout << "fabricati diem"; 
}

我使用以下命令解析此命令：

I'm parsing this using following command:

clang -Xclang -ast-dump -fsyntax-only lambda.cpp

问题是，clang也解析头部内容。结果，我有相当大（〜3000行）文件与无用的（为我的）内容。

The problem is that clang parses also headers content. As a result, I've got quite big (~3000 lines) file with useless (for me) content.

如何在生成AST时排除标题？

How to exclude headers when generating AST?

推荐答案

clang-check c $ c> clang-check 具有 -ast-dump-filter =< string> 选项

clang-check might be useful on the matter, clang-check has option -ast-dump-filter=<string> documented as follow

-ast-dump-filter =&string; - 与-ast-dump或-ast-print一起使用，只转储/打印在
限定名中具有某个子字符串的AST声明节点。当 clang-check时，使用-ast-list列出所有可过滤的声明节点
名称。

-ast-dump-filter=<string> - Use with -ast-dump or -ast-print to dump/print only AST declaration nodes having a certain substring in a qualified name. Use -ast-list to list all filterable declaration node names.

使用示例代码（lambda.cpp）上的 -ast-dump-filter = my_lambda 运行

#include <iostream>

void my_lambda()
{
    auto lambda = [](auto x, auto y) {return x + y;};
    std::cout << "fabricati diem"; 
}

它只转储匹配的声明节点 FunctionDecl my_lambda'void （void）'

It dumps only matched declaration node FunctionDecl my_lambda 'void (void)'

这是命令行参数和输出中的几行。

Here is the command line arguments and few lines from output.

$ clang-check -extra-arg=-std=c++1y -ast-dump -ast-dump-filter=my_lambda lambda.cpp --

FunctionDecl 0x2ddf630 <lambda.cpp:3:1, line:7:1> line:3:6 my_lambda 'void (void)'
`-CompoundStmt 0x2de1558 <line:4:1, line:7:1>
  |-DeclStmt 0x2de0960 <line:5:9, col:57>

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