如何导出类函数，但不是在DLL中的整个类 [英] How do I export class functions, but not the entire class in a DLL

问题描述

我开发了一个Win32 DLL，提供下面的细节，并想为函数Connnect和LogOut创建一个CLI / C ++包装。

I have developed a Win32 DLL, providing the details below, and want to create a CLI/C++ wrapper for the functions Connnect and LogOut.

类和函数可以从DLL导出。

I know that entire classes and functions can be exported from a DLL.

class CClientLib
{
 public:
CClientLib (void);
// TODO: add your methods here.
__declspec(dllexport) bool Connect(char* strAccountUID,char* strAccountPWD);
__declspec(dllexport) void LogOut();

 private :

    Account::Ref UserAccount ;
void set_ActiveAccount(Account::Ref act)
{
   // Set the active account
}

Account::Ref get_ActiveAccount()
{
  return UserAccount;
    }

};

我想让类作为导出的函数，Connect和LogOut，使用函数set / get 。

I want to have the class as the exported functions, Connect and LogOut, uses the function set / get.

只能导出Connect和LogOut函数，而不是整个类。

Is it possible only to export the functions Connect and LogOut, and not the entire class.

推荐答案

我建议声明一个将被导出的接口，然后通过内部类实现它。

I would recommend to declare an interface that will be exported and then implement it by your internal class.

class __declspec(dllexport) IClientLib {
 public:
    virtual bool Connect(char* strAccountUID,char* strAccountPWD) = 0;
    virtual void LogOut() = 0;
};

class CClientLib: public IClientLib {
...
};

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