C ++原始指针和std :: shared_ptr [英] C++ raw pointer and std::shared_ptr
问题描述
我正在使用 std :: shared_ptr ，在我的软件开发期间，我遇到了一对夫妇
的情况，让我怀疑内存管理。我有一个第三方库，
给我总是从函数的原始指针，在我的代码中我将它们
转换为 std :: shared_ptr （从std而不是boost。顺便说一下，
的区别是什么？）。所以让我们说，我有以下代码：
I am working with std::shared_ptr and during my software development I met a couple
of cases that let me doubt about memory management. I had a third party library that
gave me always raw pointers from functions and in my code I was transforming them
into std::shared_ptr (from std and not from boost. By the way what is the difference between
the two?). So let's say I have the following code:
ClassA* raw = new ClassA;
std::shared_ptr<ClassA> shared(raw);
当共享指针超出范围时，现在会发生什么？
现在我退出函数）。 ClassA 对象是否仍然存在，因为原始指针
指向它？
What happens now when the shared pointer goes out of scope (let's say it was declared locally in a function
and now I am exiting the function). Will the ClassA object still exist because a raw pointer
is pointing to it?
推荐答案
不会。通过给指针shared_ptr你给予shared_ptr的责任删除它。当引用它的最后一个shared_ptr对象不再存在时，它会这样做。原始指针不计数。
No it won't. By giving the pointer to shared_ptr you are giving shared_ptr the responsibilty for deleteing it. It will do this when the last shared_ptr object refering to it no longer exists. Raw pointers don't count.
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