如何将“n”个字符的副本写入ostream，就像在python中一样 [英] How to write 'n' copies of a character to ostream like in python

问题描述

在python中，以下指令： print'a'* 5 将输出 aaaaa 。如何在C ++中结合 std :: ostream 写一个类似的东西，以避免 for 构造？

In python, the following instruction: print 'a'*5 would output aaaaa. How would one write something similar in C++ in conjunction with std::ostreams in order to avoid a for construct?

推荐答案

显而易见的方式是使用 fill_n ：

The obvious way would be with fill_n:

std::fill_n(std::ostream_iterator<char>(std::cout), 5, 'a');

另一种可能性是只需构造一个字符串：

Another possibility would be be to just construct a string:

std:cout << std::string(5, 'a');

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