不明确的C ++编译器错误 [英] Ambiguous C++ compiler error
问题描述
以下位代码无法编译。错误似乎是对合并例程的某种模糊调用。我的理解是STL有一个合并例程,在std命名空间中找到,但就我可以告诉名称合并在下面的代码应该是唯一的。
如果我将合并重命名为xmerge,一切正常。问题是什么?哪里是来自的名称冲突?
#include< iostream>
#include #include< vector>
template< typename InputIterator1,
typename InputIterator2,
typename OutputIterator>
void merge(const InputIterator1 begin1,const InputIterator1 end1,
const InputIterator2 begin2,const InputIterator2 end2,
OutputIterator out)
{
InputIterator1 itr1 = begin1;
InputIterator2 itr2 = begin2;
while((itr1!= end1)&&(itr2!= end2))
{
if(* itr1 <* itr2)
* out = * itr1 ,++ itr1;
else
* out = * itr2,++ itr2;
++ out;
}
while(itr1!= end1)* out ++ = * itr1 ++;
while(itr2!= end2)* out ++ = * itr2 ++;
}
int main()
{
std :: vector< int> l1;
std :: vector< int> l2;
std :: vector< int> merged_list;
merge(l1.begin(),l1.end(),
l2.begin(),l2.end(),
std :: back_inserter(merged_list)) ;
return 0;
}
编译器 The following bit of code fails to compile. The error seems to be some kind of ambigous call to the merge routine. My understanding is that STL has a merge routine found in the std namespace, but as far as I can tell the name merge in the code below should be unique. If I rename merge to xmerge, everything works. What could the problem be? where is the name clash coming from?
Compiler is getting confused between your 这篇关于不明确的C ++编译器错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!合并
函数和算法中定义的
std :: merge
>。使用 :: merge
可删除此模糊。此调用不明确,因为编译器使用参数依赖查找在使用不合格函数名称时搜索函数。 / p> #include <iostream>
#include <iterator>
#include <vector>
template<typename InputIterator1,
typename InputIterator2,
typename OutputIterator>
void merge(const InputIterator1 begin1, const InputIterator1 end1,
const InputIterator2 begin2, const InputIterator2 end2,
OutputIterator out)
{
InputIterator1 itr1 = begin1;
InputIterator2 itr2 = begin2;
while ((itr1 != end1) && (itr2 != end2))
{
if (*itr1 < *itr2)
*out = *itr1, ++itr1;
else
*out = *itr2, ++itr2;
++out;
}
while (itr1 != end1) *out++ = *itr1++;
while (itr2 != end2) *out++ = *itr2++;
}
int main()
{
std::vector<int> l1;
std::vector<int> l2;
std::vector<int> merged_list;
merge(l1.begin(),l1.end(),
l2.begin(),l2.end(),
std::back_inserter(merged_list));
return 0;
}
merge
function and the std::merge
defined in the algorithm
. Use ::merge
to remove this ambiguity. This call is ambiguous as compiler is using Argument Dependendent Lookup to search for the function when unqualified function name is used.