如何初始化boost :: random :: discrete_distribution使用std :: vector？ [英] How to initialize boost::random::discrete_distribution using std::vector?

问题描述

我想用 std :: vector< double> 初始化 boost :: random :: discrete_distribution 。

我的问题是，如果我用数组初始化它，就像官方示例：

My problem is that if I initialize it with an array, like in the official example:

double probabilities[] = {
    0.5, 0.1, 0.1, 0.1, 0.1, 0.1
};
boost::random::discrete_distribution<> dist(probabilities);

然而，如果我用一个 std :: vector 初始化它，它的行为就像它只有一个元素可能性为1.0。

However if I initialize it with a std::vector, then it behaves like if it has only one element with probability 1.0.

你能告诉我什么是初始化正确的方法boost :: random :: discrete_distribution< c $ c>有一个向量？

Can you tell me what is the right way of initializing a boost::random::discrete_distribution<> with a vector?

推荐答案

类似乎有一个构造函数获取迭代器范围。这将与这样的向量一起使用：

The class seems to have a constructor that takes an iterator range. This would be used with a vector like this:

std::vector<double> probs = ...;
boost::random::discrete_distribution<> dist(probs.begin(), probs.end());

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