如何在C ++程序中获得调试/释放条件编译 [英] How to obtain debug/release conditional compiling in C++ program

问题描述

在一个大的C ++ / Qt / QMake / qtcreator项目中，我想执行一些测试，但是只有当我使用debug标志进行编译。

In a large C++/Qt/QMake/qtcreator project I would like to perform some tests, but only when I am compiling with the debug flag.

一个方法告诉g ++的代码的一些小部分只能在调试模式下编译？

Is there a way to tell g++ that some small parts of the code have to be compiled only in debug mode ?

推荐答案

这样做的标准方法是依赖于 NDEBUG ，< cassert> 中定义的宏 assert（）：

The standard way to do this is to depend on the macro NDEBUG, which is used by the macro assert() defined in <cassert>:

#ifdef NDEBUG
  // release mode code
#else
  // debug mode code
#endif

#ifdef code> #ifndef ，当然 #else 分支是可选的。

The opposite of #ifdef is #ifndef, and of course #else branches are optional.

如果此宏无效（无论何种原因），您

If this macro doesn't work (for whatever reason), you

1. 可以尝试 QT_NO_DEBUG ，Qt使用与 Q_ASSERT（）类似的目的;和

1. can try the macro QT_NO_DEBUG, which Qt uses for a similar purpose with Q_ASSERT(); and

应修正它，使得 NDEBUG 它需要< cassert> 才能正常工作，您使用的代码可能取决于它。

should fix it so that NDEBUG is (un)defined correctly; it's required for <cassert> to work properly, and code you use may depend on it.

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