拦截所有的Ajax调用？ [英] intercept all ajax calls?

问题描述

我试图拦截所有这些都是为了AJAX调用，以检查是否是Ajax响应包含了我送的JSON从我的PHP脚本的特定错误code（codeS：ACCESS_DENIED，SYSTEM_ERROR，NOT_FOUND）。

I'm trying to intercept all AJAX calls in order to check if that AJAX response contains specific error code that I send as JSON from my PHP script (codes: ACCESS_DENIED, SYSTEM_ERROR, NOT_FOUND).

我知道我们可以做这样的事情：

I know one can do something like this:

$('.log').ajaxSuccess(function(e, xhr, settings) {
});

但是 - 这是否工作，只有当的ajaxSuccess事件冒泡到的.log DIV？我对么？我能达到我想要通过结合的ajaxSuccess事件文件？

But - does this work only if "ajaxSuccess" event bubble up to .log div? Am I correct? Can I achieve what I want by binding "ajaxSuccess" event to document?

$(document).ajaxSuccess(function(e, xhr, settings) {
});

P中。 S.任何见解，欢迎，jQuery的或生的JavaScript。谢谢！

P. S. Any insights are welcome, jQuery or raw javascript. Thanks!

推荐答案

从 HTTP：//api.jquery。 COM /的ajaxSuccess / ：

当一个Ajax请求成功完成，jQuery的触发事件的ajaxSuccess。已注册的.ajaxSuccess（）方法中的任何和所有的处理程序在这个时候被执行。

Whenever an Ajax request completes successfully, jQuery triggers the ajaxSuccess event. Any and all handlers that have been registered with the .ajaxSuccess() method are executed at this time.

所以选择不定义你在哪里恶补的情况下（因为，说实话，AJAX事件由于其性质并不会从DOM元素开始）的位置，而是定义了一个范围，它的处理会被拖欠（即这将poitn到/这些元素（S））。

So the selector doesn't define the position where you are "catching" the event (because, honestly, ajax event by its nature doesn't start from a DOM element), but rather defines a scope to which the handling will be defaulted (i.e. this will poitn to that/those element(s)).

在总结 - 它应该是正是你想要的。

In summary - it should be exactly what you wish for

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