在内联函数中__LINE__的行为 [英] Behavior of __LINE__ in inline functions

问题描述

我有一个宏将行号和文件名传递给错误处理程序：

I have a macro that passes the line number and file name to an error handler:

#define SYSTEM_FAILURE (error_code, comment) \
   System_Failure((error_code), (comment), __LINE__, __FILE__);

__ LINE __ 在内联函数中？

file.h:
inline int divide(int x, int y)
{
    if (y == 0)
    {
        SYSTEM_FAILURE(ENUM_DIVIDE_BY_ZERO, "divide by zero error");
    }
    return x/y;
}

将 __ LINE __ 头文件中的行号或者调用内联函数的源文件的行号（假设编译器在源代码中做了粘贴）？

Will __LINE__ contain the line number within the header file, or the line number of the source file where the inline function is called (assuming compiler does a "paste" in the source code)?

推荐答案

在C和C ++中，宏不是（大部分）用实际代码的任何知识进行评估，并且在代码之前处理（因此名称为预处理器）。因此， __ FILE __ 将计算为file.h， __ LINE __ 将计算与该行对应的行号其中 SYSTEM_FAILURE 出现在file.h中。

In C and C++, macros aren't (for the most part) evaluated with any knowledge of the actual code and are processed before the code (hence the name "preprocessor"). Therefore, __FILE__ would evaluate to "file.h", and __LINE__ would evaluate to the line number corresponding to the line on which SYSTEM_FAILURE appears in file.h.

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